#Python while loop code#

Since the value of i is now 11, the condition of the while loop ( i <= 10) becomes False and the loop gets stopped and the rest of the statements after the while loop gets executed. In the tenth iteration, when i becomes 10, 140 gets printed and i = i+1 makes the value of i equal to 11.

In the third iteration, again the condition of the loop is satisfied and 42 gets printed on the screen. Therefore, again the statements in the body are executed - 14*i ( 14*2 = 28 ) gets printed and then i = i+1 increases the value of i by 1 making it 3. In the second iteration, again the condition of the loop is satisfied (2 is less than 10). Therefore, the statements in the body of while are executed - 14*i ( 14*1 = 14 ) gets printed and then i = i+1 increases the value of i by 1 making it 2. In the first iteration, the condition is satisfied (1 is less than 10). In this example, the condition of the while loop is i<=10. Therefore, ten iterations took place in the above example. This time, the condition n <= 10 becomes False and the loop gets terminated.Ĭhecking the condition and executing the body consists of one iteration. Now, n = n + 1 increases the value to n to 11. In this way, when the value of n becomes 10, again the condition n <= 10 is True for the tenth time and 10 gets printed. So, again the value of n i.e., 2 gets printed and the value of n is increased to 3. This time also n <= 10 is True because the value of n is 2. 1 is printed and n = n + 1 increases the value of n by 1. Since the value of n is 1 which is less than 10, the condition becomes True and the statements in the body are executed. While n <= 10: → The condition n <= 10 is checked.

These two statements will get executed only if the condition is True. The body of the while loop consists of print(n) and n = n + 1. If you want to repeat only when user use upper Y then you need nested loop def second_option():įor key, value in searched_service.The condition of the while loop is n <= 10. Search_again = input('Do you want to search again ?') Upper char informs that it default answer. I also use lower and upper char in because it is popular method to show that it will use Y as default value when you only press Enter. This way I don't have to write Y (or y) to repeat it - it make life easier and it is popular method in many tools. And if user selects any other value or simply press only Enter then it assumes that user want to repeat it. If user selects N or lower n then it exits loop and it goes back to menu. You should run all in while True without running again second_option().Īnd you should exit function to go back to menu.

When you exit menu() then it will return to second_option() And when you exit last second_option() then it returns to previous second_option() and it looks like it didn't exit loop.Īnd similar problem can make menu() in second_option(). You may have problem because inside second_option() you run again second_option() - it is recursion. I'm getting the following output everything seems fine but the last should be to enter name to search but I guess I'm stuck in the loop Search_again = input('Do you want to search again (Y/N)?')

Print(' ',len(searched_service), 'course have been found: ' ) Print(' Course ID: ' + key + ' Course Name: '+ value+' Course Price: ' + value) Print(' ',len(searched_service), 'courses have been found: ' )įor key, value in searched_ems(): Search = input('Enter name of application to see if it is available in our database:')

#Python while loop code#

I'm using while loop but my code is not correct somehow. I have written a function that ask the user for input and searches from a predefined dictionary, after showing the results the function ask the user to search again.